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20 #include <basegfx/polygon/b2dpolygonclipper.hxx>
21 #include <basegfx/polygon/b2dpolygontools.hxx>
22 #include <basegfx/numeric/ftools.hxx>
23 #include <basegfx/matrix/b2dhommatrix.hxx>
24 #include <basegfx/polygon/b2dpolypolygoncutter.hxx>
25 #include <basegfx/polygon/b2dpolygoncutandtouch.hxx>
26 #include <basegfx/polygon/b2dpolypolygontools.hxx>
27 #include <basegfx/curve/b2dcubicbezier.hxx>
28 #include <basegfx/utils/rectcliptools.hxx>
29 #include <basegfx/matrix/b2dhommatrixtools.hxx>
35 B2DPolyPolygon
clipPolygonOnParallelAxis(const B2DPolygon
& rCandidate
, bool bParallelToXAxis
, bool bAboveAxis
, double fValueOnOtherAxis
, bool bStroke
)
37 B2DPolyPolygon aRetval
;
39 if(rCandidate
.count())
41 const B2DRange
aCandidateRange(getRange(rCandidate
));
43 if(bParallelToXAxis
&& fTools::moreOrEqual(aCandidateRange
.getMinY(), fValueOnOtherAxis
))
45 // completely above and on the clip line. also true for curves.
49 aRetval
.append(rCandidate
);
52 else if(bParallelToXAxis
&& fTools::lessOrEqual(aCandidateRange
.getMaxY(), fValueOnOtherAxis
))
54 // completely below and on the clip line. also true for curves.
58 aRetval
.append(rCandidate
);
61 else if(!bParallelToXAxis
&& fTools::moreOrEqual(aCandidateRange
.getMinX(), fValueOnOtherAxis
))
63 // completely right of and on the clip line. also true for curves.
67 aRetval
.append(rCandidate
);
70 else if(!bParallelToXAxis
&& fTools::lessOrEqual(aCandidateRange
.getMaxX(), fValueOnOtherAxis
))
72 // completely left of and on the clip line. also true for curves.
76 aRetval
.append(rCandidate
);
81 // add cuts with axis to polygon, including bezier segments
82 // Build edge to cut with. Make it a little big longer than needed for
83 // numerical stability. We want to cut against the edge seen as endless
84 // ray here, but addPointsAtCuts() will limit itself to the
85 // edge's range ]0.0 .. 1.0[.
86 const double fSmallExtension((aCandidateRange
.getWidth() + aCandidateRange
.getHeight()) * (0.5 * 0.1));
87 const B2DPoint
aStart(
88 bParallelToXAxis
? aCandidateRange
.getMinX() - fSmallExtension
: fValueOnOtherAxis
,
89 bParallelToXAxis
? fValueOnOtherAxis
: aCandidateRange
.getMinY() - fSmallExtension
);
91 bParallelToXAxis
? aCandidateRange
.getMaxX() + fSmallExtension
: fValueOnOtherAxis
,
92 bParallelToXAxis
? fValueOnOtherAxis
: aCandidateRange
.getMaxY() + fSmallExtension
);
93 const B2DPolygon
aCandidate(addPointsAtCuts(rCandidate
, aStart
, aEnd
));
94 const sal_uInt32
nPointCount(aCandidate
.count());
95 const sal_uInt32
nEdgeCount(aCandidate
.isClosed() ? nPointCount
: nPointCount
- 1);
99 for(sal_uInt32
a(0); a
< nEdgeCount
; a
++)
101 aCandidate
.getBezierSegment(a
, aEdge
);
102 const B2DPoint
aTestPoint(aEdge
.interpolatePoint(0.5));
103 const bool bInside(bParallelToXAxis
?
104 fTools::moreOrEqual(aTestPoint
.getY(), fValueOnOtherAxis
) == bAboveAxis
:
105 fTools::moreOrEqual(aTestPoint
.getX(), fValueOnOtherAxis
) == bAboveAxis
);
109 if(!aRun
.count() || !aRun
.getB2DPoint(aRun
.count() - 1).equal(aEdge
.getStartPoint()))
111 aRun
.append(aEdge
.getStartPoint());
116 aRun
.appendBezierSegment(aEdge
.getControlPointA(), aEdge
.getControlPointB(), aEdge
.getEndPoint());
120 aRun
.append(aEdge
.getEndPoint());
125 if(bStroke
&& aRun
.count())
127 aRetval
.append(aRun
);
137 // try to merge this last and first polygon; they may have been
138 // the former polygon's start/end point
141 const B2DPolygon
aStartPolygon(aRetval
.getB2DPolygon(0));
143 if(aStartPolygon
.count() && aStartPolygon
.getB2DPoint(0).equal(aRun
.getB2DPoint(aRun
.count() - 1)))
145 // append start polygon to aRun, remove from result set
146 aRun
.append(aStartPolygon
); aRun
.removeDoublePoints();
151 aRetval
.append(aRun
);
155 // set closed flag and correct last point (which is added double now).
156 closeWithGeometryChange(aRun
);
157 aRetval
.append(aRun
);
166 B2DPolyPolygon
clipPolyPolygonOnParallelAxis(const B2DPolyPolygon
& rCandidate
, bool bParallelToXAxis
, bool bAboveAxis
, double fValueOnOtherAxis
, bool bStroke
)
168 const sal_uInt32
nPolygonCount(rCandidate
.count());
169 B2DPolyPolygon aRetval
;
171 for(sal_uInt32
a(0); a
< nPolygonCount
; a
++)
173 const B2DPolyPolygon
aClippedPolyPolygon(clipPolygonOnParallelAxis(rCandidate
.getB2DPolygon(a
), bParallelToXAxis
, bAboveAxis
, fValueOnOtherAxis
, bStroke
));
175 if(aClippedPolyPolygon
.count())
177 aRetval
.append(aClippedPolyPolygon
);
184 B2DPolyPolygon
clipPolygonOnRange(const B2DPolygon
& rCandidate
, const B2DRange
& rRange
, bool bInside
, bool bStroke
)
186 const sal_uInt32
nCount(rCandidate
.count());
187 B2DPolyPolygon aRetval
;
199 // nothing is inside an empty range
204 // everything is outside an empty range
205 return B2DPolyPolygon(rCandidate
);
209 const B2DRange
aCandidateRange(getRange(rCandidate
));
211 if(rRange
.isInside(aCandidateRange
))
213 // candidate is completely inside given range
217 return B2DPolyPolygon(rCandidate
);
221 // nothing is outside, then
228 // cutting off the outer parts of filled polygons at parallel
229 // lines to the axes is only possible for the inner part, not for
230 // the outer part which means cutting a hole into the original polygon.
231 // This is because the inner part is a logical AND-operation of
232 // the four implied half-planes, but the outer part is not.
233 // It is possible for strokes, but with creating unnecessary extra
234 // cuts, so using clipPolygonOnPolyPolygon is better there, too.
235 // This needs to be done with the topology knowledge and is unfortunately
236 // more expensive, too.
237 const B2DPolygon
aClip(createPolygonFromRect(rRange
));
239 return clipPolygonOnPolyPolygon(rCandidate
, B2DPolyPolygon(aClip
), bInside
, bStroke
);
242 // clip against the four axes of the range
243 // against X-Axis, lower value
244 aRetval
= clipPolygonOnParallelAxis(rCandidate
, true, bInside
, rRange
.getMinY(), bStroke
);
248 // against Y-Axis, lower value
249 if(aRetval
.count() == 1)
251 aRetval
= clipPolygonOnParallelAxis(aRetval
.getB2DPolygon(0), false, bInside
, rRange
.getMinX(), bStroke
);
255 aRetval
= clipPolyPolygonOnParallelAxis(aRetval
, false, bInside
, rRange
.getMinX(), bStroke
);
260 // against X-Axis, higher value
261 if(aRetval
.count() == 1)
263 aRetval
= clipPolygonOnParallelAxis(aRetval
.getB2DPolygon(0), true, !bInside
, rRange
.getMaxY(), bStroke
);
267 aRetval
= clipPolyPolygonOnParallelAxis(aRetval
, true, !bInside
, rRange
.getMaxY(), bStroke
);
272 // against Y-Axis, higher value
273 if(aRetval
.count() == 1)
275 aRetval
= clipPolygonOnParallelAxis(aRetval
.getB2DPolygon(0), false, !bInside
, rRange
.getMaxX(), bStroke
);
279 aRetval
= clipPolyPolygonOnParallelAxis(aRetval
, false, !bInside
, rRange
.getMaxX(), bStroke
);
288 B2DPolyPolygon
clipPolyPolygonOnRange(const B2DPolyPolygon
& rCandidate
, const B2DRange
& rRange
, bool bInside
, bool bStroke
)
290 const sal_uInt32
nPolygonCount(rCandidate
.count());
291 B2DPolyPolygon aRetval
;
303 // nothing is inside an empty range
308 // everything is outside an empty range
315 for(sal_uInt32
a(0); a
< nPolygonCount
; a
++)
317 const B2DPolyPolygon
aClippedPolyPolygon(clipPolygonOnRange(rCandidate
.getB2DPolygon(a
), rRange
, bInside
, bStroke
));
319 if(aClippedPolyPolygon
.count())
321 aRetval
.append(aClippedPolyPolygon
);
327 // for details, see comment in clipPolygonOnRange for the "cutting off
328 // the outer parts of filled polygons at parallel lines" explanations
329 const B2DPolygon
aClip(createPolygonFromRect(rRange
));
331 return clipPolyPolygonOnPolyPolygon(rCandidate
, B2DPolyPolygon(aClip
), bInside
, bStroke
);
337 B2DPolyPolygon
clipPolyPolygonOnPolyPolygon(const B2DPolyPolygon
& rCandidate
, const B2DPolyPolygon
& rClip
, bool bInside
, bool bStroke
)
339 B2DPolyPolygon aRetval
;
341 if(rCandidate
.count() && rClip
.count())
343 // one or both are no rectangle - go the hard way and clip PolyPolygon
344 // against PolyPolygon...
347 // line clipping, create line snippets by first adding all cut points and
348 // then marching along the edges and detecting if they are inside or outside
350 for(sal_uInt32
a(0); a
< rCandidate
.count(); a
++)
352 // add cuts with clip to polygon, including bezier segments
353 const B2DPolygon
aCandidate(addPointsAtCuts(rCandidate
.getB2DPolygon(a
), rClip
));
354 const sal_uInt32
nPointCount(aCandidate
.count());
355 const sal_uInt32
nEdgeCount(aCandidate
.isClosed() ? nPointCount
: nPointCount
- 1);
356 B2DCubicBezier aEdge
;
359 for(sal_uInt32
b(0); b
< nEdgeCount
; b
++)
361 aCandidate
.getBezierSegment(b
, aEdge
);
362 const B2DPoint
aTestPoint(aEdge
.interpolatePoint(0.5));
363 const bool bIsInside(utils::isInside(rClip
, aTestPoint
) == bInside
);
369 aRun
.append(aEdge
.getStartPoint());
374 aRun
.appendBezierSegment(aEdge
.getControlPointA(), aEdge
.getControlPointB(), aEdge
.getEndPoint());
378 aRun
.append(aEdge
.getEndPoint());
385 aRetval
.append(aRun
);
393 // try to merge this last and first polygon; they may have been
394 // the former polygon's start/end point
397 const B2DPolygon
aStartPolygon(aRetval
.getB2DPolygon(0));
399 if(aStartPolygon
.count() && aStartPolygon
.getB2DPoint(0).equal(aRun
.getB2DPoint(aRun
.count() - 1)))
401 // append start polygon to aRun, remove from result set
402 aRun
.append(aStartPolygon
); aRun
.removeDoublePoints();
407 aRetval
.append(aRun
);
413 // check for simplification with ranges if !bStroke (handling as stroke is more simple),
414 // but also only when bInside, else the simplification may lead to recursive calls (see
415 // calls to clipPolyPolygonOnPolyPolygon in clipPolyPolygonOnRange and clipPolygonOnRange)
416 if (bInside
&& basegfx::utils::isRectangle(rClip
))
418 // #i125349# detect if both given PolyPolygons are indeed ranges
419 if (basegfx::utils::isRectangle(rCandidate
))
421 // both are rectangle
422 if(rCandidate
.getB2DRange().equal(rClip
.getB2DRange()))
424 // if both are equal -> no change
429 // not equal -> create new intersection from both ranges,
430 // but much cheaper based on the ranges
431 basegfx::B2DRange
aIntersectionRange(rCandidate
.getB2DRange());
433 aIntersectionRange
.intersect(rClip
.getB2DRange());
435 if(aIntersectionRange
.isEmpty())
437 // no common IntersectionRange -> the clip will be empty
438 return B2DPolyPolygon();
442 // use common aIntersectionRange as result, convert
443 // to expected utils::PolyPolygon form
444 return basegfx::B2DPolyPolygon(
445 basegfx::utils::createPolygonFromRect(aIntersectionRange
));
451 // rClip is rectangle -> clip rCandidate on rRectangle, use the much
452 // cheaper and numerically more stable clipping against a range
453 return clipPolyPolygonOnRange(rCandidate
, rClip
.getB2DRange(), bInside
, bStroke
);
458 B2DPolyPolygon
aMergePolyPolygonA(rClip
);
460 // First solve all polygon-self and polygon-polygon intersections.
461 // Also get rid of some not-needed polygons (neutral, no area -> when
462 // no intersections, these are tubes).
463 // Now it is possible to correct the orientations in the cut-free
464 // polygons to values corresponding to painting the utils::PolyPolygon with
465 // a XOR-WindingRule.
466 aMergePolyPolygonA
= solveCrossovers(aMergePolyPolygonA
);
467 aMergePolyPolygonA
= stripNeutralPolygons(aMergePolyPolygonA
);
468 aMergePolyPolygonA
= correctOrientations(aMergePolyPolygonA
);
472 // if we want to get the outside of the clip polygon, make
473 // it a 'Hole' in topological sense
474 aMergePolyPolygonA
.flip();
477 B2DPolyPolygon
aMergePolyPolygonB(rCandidate
);
479 // prepare 2nd source polygon in same way
480 aMergePolyPolygonB
= solveCrossovers(aMergePolyPolygonB
);
481 aMergePolyPolygonB
= stripNeutralPolygons(aMergePolyPolygonB
);
482 aMergePolyPolygonB
= correctOrientations(aMergePolyPolygonB
);
484 // to clip against each other, concatenate and solve all
485 // polygon-polygon crossovers. polygon-self do not need to
486 // be solved again, they were solved in the preparation.
487 aRetval
.append(aMergePolyPolygonA
);
488 aRetval
.append(aMergePolyPolygonB
);
489 aRetval
= solveCrossovers(aRetval
);
491 // now remove neutral polygons (closed, but no area). In a last
492 // step throw away all polygons which have a depth of less than 1
493 // which means there was no logical AND at their position. For the
494 // not-inside solution, the clip was flipped to define it as 'Hole',
495 // so the removal rule is different here; remove all with a depth
496 // of less than 0 (aka holes).
497 aRetval
= stripNeutralPolygons(aRetval
);
498 aRetval
= stripDispensablePolygons(aRetval
, bInside
);
505 B2DPolyPolygon
clipPolygonOnPolyPolygon(const B2DPolygon
& rCandidate
, const B2DPolyPolygon
& rClip
, bool bInside
, bool bStroke
)
507 B2DPolyPolygon aRetval
;
509 if(rCandidate
.count() && rClip
.count())
511 aRetval
= clipPolyPolygonOnPolyPolygon(B2DPolyPolygon(rCandidate
), rClip
, bInside
, bStroke
);
518 * let a plane be defined as
522 * and a ray be defined as
526 * substitute and rearranging yields
528 * t = -(a.n+d)/(n.(b-a))
530 * if the denominator is zero, the line is either
531 * contained in the plane or parallel to the plane.
532 * in either case, there is no intersection.
533 * if numerator and denominator are both zero, the
534 * ray is contained in the plane.
537 struct scissor_plane
{
538 double nx
,ny
; // plane normal
539 double d
; // [-] minimum distance from origin
540 sal_uInt32 clipmask
; // clipping mask, e.g. 1000 1000
545 * polygon clipping rules (straight out of Foley and Van Dam)
546 * ===========================================================
547 * current |next |emit
548 * ____________________________________
549 * inside |inside |next
550 * inside |outside |intersect with clip plane
551 * outside |outside |nothing
552 * outside |inside |intersect with clip plane follwed by next
555 sal_uInt32
scissorLineSegment( ::basegfx::B2DPoint
*in_vertex
, // input buffer
556 sal_uInt32 in_count
, // number of verts in input buffer
557 ::basegfx::B2DPoint
*out_vertex
, // output buffer
558 scissor_plane
const *pPlane
, // scissoring plane
559 const ::basegfx::B2DRectangle
&rR
) // clipping rectangle
562 sal_uInt32 out_count
=0;
564 // process all the verts
565 for(sal_uInt32 i
=0; i
<in_count
; i
++) {
567 // vertices are relative to the coordinate
568 // system defined by the rectangle.
569 ::basegfx::B2DPoint
*curr
= &in_vertex
[i
];
570 ::basegfx::B2DPoint
*next
= &in_vertex
[(i
+1)%in_count
];
572 // perform clipping judgement & mask against current plane.
573 sal_uInt32 clip
= pPlane
->clipmask
& ((getCohenSutherlandClipFlags(*curr
,rR
)<<4)|getCohenSutherlandClipFlags(*next
,rR
));
575 if(clip
==0) { // both verts are inside
576 out_vertex
[out_count
++] = *next
;
578 else if((clip
&0x0f) && (clip
&0xf0)) { // both verts are outside
580 else if((clip
&0x0f) && (clip
&0xf0)==0) { // curr is inside, next is outside
582 // direction vector from 'current' to 'next', *not* normalized
583 // to bring 't' into the [0<=x<=1] interval.
584 ::basegfx::B2DPoint
dir((*next
)-(*curr
));
586 double denominator
= ( pPlane
->nx
*dir
.getX() +
587 pPlane
->ny
*dir
.getY() );
588 double numerator
= ( pPlane
->nx
*curr
->getX() +
589 pPlane
->ny
*curr
->getY() +
591 double t
= -numerator
/denominator
;
593 // calculate the actual point of intersection
594 ::basegfx::B2DPoint
intersection( curr
->getX()+t
*dir
.getX(),
595 curr
->getY()+t
*dir
.getY() );
597 out_vertex
[out_count
++] = intersection
;
599 else if((clip
&0x0f)==0 && (clip
&0xf0)) { // curr is outside, next is inside
601 // direction vector from 'current' to 'next', *not* normalized
602 // to bring 't' into the [0<=x<=1] interval.
603 ::basegfx::B2DPoint
dir((*next
)-(*curr
));
605 double denominator
= ( pPlane
->nx
*dir
.getX() +
606 pPlane
->ny
*dir
.getY() );
607 double numerator
= ( pPlane
->nx
*curr
->getX() +
608 pPlane
->ny
*curr
->getY() +
610 double t
= -numerator
/denominator
;
612 // calculate the actual point of intersection
613 ::basegfx::B2DPoint
intersection( curr
->getX()+t
*dir
.getX(),
614 curr
->getY()+t
*dir
.getY() );
616 out_vertex
[out_count
++] = intersection
;
617 out_vertex
[out_count
++] = *next
;
624 B2DPolygon
clipTriangleListOnRange( const B2DPolygon
& rCandidate
,
625 const B2DRange
& rRange
)
629 if( !(rCandidate
.count()%3) )
631 const int scissor_plane_count
= 4;
633 scissor_plane sp
[scissor_plane_count
];
637 sp
[0].d
= -(rRange
.getMinX());
638 sp
[0].clipmask
= (RectClipFlags::LEFT
<< 4) | RectClipFlags::LEFT
; // 0001 0001
641 sp
[1].d
= +(rRange
.getMaxX());
642 sp
[1].clipmask
= (RectClipFlags::RIGHT
<< 4) | RectClipFlags::RIGHT
; // 0010 0010
645 sp
[2].d
= -(rRange
.getMinY());
646 sp
[2].clipmask
= (RectClipFlags::TOP
<< 4) | RectClipFlags::TOP
; // 0100 0100
649 sp
[3].d
= +(rRange
.getMaxY());
650 sp
[3].clipmask
= (RectClipFlags::BOTTOM
<< 4) | RectClipFlags::BOTTOM
; // 1000 1000
652 // retrieve the number of vertices of the triangulated polygon
653 const sal_uInt32 nVertexCount
= rCandidate
.count();
657 // Upper bound for the maximal number of vertices when intersecting an
658 // axis-aligned rectangle with a triangle in E2
660 // The rectangle and the triangle are in general position, and have 4 and 3
661 // vertices, respectively.
663 // Lemma: Since the rectangle is a convex polygon ( see
664 // http://mathworld.wolfram.com/ConvexPolygon.html for a definition), and
665 // has no holes, it follows that any straight line will intersect the
666 // rectangle's border line at utmost two times (with the usual
667 // tie-breaking rule, if the intersection exactly hits an already existing
668 // rectangle vertex, that this intersection is only attributed to one of
669 // the adjoining edges). Thus, having a rectangle intersected with
670 // a half-plane (one side of a straight line denotes 'inside', the
671 // other 'outside') will at utmost add _one_ vertex to the resulting
672 // intersection polygon (adding two intersection vertices, and removing at
673 // least one rectangle vertex):
676 // +--+-----------------+
682 // +--------------------+
684 // Proof: If the straight line intersects the rectangle two
685 // times, it does so for distinct edges, i.e. the intersection has
686 // minimally one of the rectangle's vertices on either side of the straight
687 // line (but maybe more). Thus, the intersection with a half-plane has
688 // minimally _one_ rectangle vertex removed from the resulting clip
689 // polygon, and therefore, a clip against a half-plane has the net effect
690 // of adding at utmost _one_ vertex to the resulting clip polygon.
692 // Theorem: The intersection of a rectangle and a triangle results in a
693 // polygon with at utmost 7 vertices.
695 // Proof: The inside of the triangle can be described as the consecutive
696 // intersection with three half-planes. Together with the lemma above, this
697 // results in at utmost 3 additional vertices added to the already existing 4
698 // rectangle vertices.
700 // This upper bound is attained with the following example configuration:
724 // As we need to scissor all triangles against the
725 // output rectangle we employ an output buffer for the
726 // resulting vertices. the question is how large this
727 // buffer needs to be compared to the number of
728 // incoming vertices. this buffer needs to hold at
729 // most the number of original vertices times '7'. see
730 // figure above for an example. scissoring triangles
731 // with the cohen-sutherland line clipping algorithm
732 // as implemented here will result in a triangle fan
733 // which will be rendered as separate triangles to
734 // avoid pipeline stalls for each scissored
735 // triangle. creating separate triangles from a
736 // triangle fan produces (n-2)*3 vertices where n is
737 // the number of vertices of the original triangle
738 // fan. for the maximum number of 7 vertices of
739 // resulting triangle fans we therefore need 15 times
740 // the number of original vertices.
742 //const size_t nBufferSize = sizeof(vertex)*(nVertexCount*16);
743 //vertex *pVertices = (vertex*)alloca(nBufferSize);
744 //sal_uInt32 nNumOutput = 0;
746 // we need to clip this triangle against the output rectangle
747 // to ensure that the resulting texture coordinates are in
748 // the valid range from [0<=st<=1]. under normal circumstances
749 // we could use the BORDERCOLOR renderstate but some cards
750 // seem to ignore this feature.
751 ::basegfx::B2DPoint stack
[3];
752 unsigned int clipflag
= 0;
754 for(sal_uInt32 nIndex
=0; nIndex
<nVertexCount
; ++nIndex
)
759 stack
[2] = rCandidate
.getB2DPoint(nIndex
);
761 // clipping judgement
762 clipflag
|= unsigned(!(rRange
.isInside(stack
[2])));
766 // consume vertices until a single separate triangle has been visited.
769 // if any of the last three vertices was outside
770 // we need to scissor against the destination rectangle
773 ::basegfx::B2DPoint buf0
[16];
774 ::basegfx::B2DPoint buf1
[16];
776 sal_uInt32 vertex_count
= 3;
778 // clip against all 4 planes passing the result of
779 // each plane as the input to the next using a double buffer
780 vertex_count
= scissorLineSegment(stack
,vertex_count
,buf1
,&sp
[0],rRange
);
781 vertex_count
= scissorLineSegment(buf1
,vertex_count
,buf0
,&sp
[1],rRange
);
782 vertex_count
= scissorLineSegment(buf0
,vertex_count
,buf1
,&sp
[2],rRange
);
783 vertex_count
= scissorLineSegment(buf1
,vertex_count
,buf0
,&sp
[3],rRange
);
785 if(vertex_count
>= 3)
787 // convert triangle fan back to triangle list.
788 ::basegfx::B2DPoint
v0(buf0
[0]);
789 ::basegfx::B2DPoint
v1(buf0
[1]);
790 for(sal_uInt32 i
=2; i
<vertex_count
; ++i
)
792 ::basegfx::B2DPoint
v2(buf0
[i
]);
802 // the last triangle has not been altered, simply copy to result
803 for(basegfx::B2DPoint
& i
: stack
)
817 } // end of namespace utils
818 } // end of namespace basegfx
820 /* vim:set shiftwidth=4 softtabstop=4 expandtab: */