mediagoblin/tools/licenses.py

   1 # GNU MediaGoblin -- federated, autonomous media hosting
   2 # Copyright (C) 2011, 2012 MediaGoblin contributors.  See AUTHORS.
   3 #
   4 # This program is free software: you can redistribute it and/or modify
   5 # it under the terms of the GNU Affero General Public License as published by
   6 # the Free Software Foundation, either version 3 of the License, or
   7 # (at your option) any later version.
   8 #
   9 # This program is distributed in the hope that it will be useful,
  10 # but WITHOUT ANY WARRANTY; without even the implied warranty of
  11 # MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the
  12 # GNU Affero General Public License for more details.
  13 #
  14 # You should have received a copy of the GNU Affero General Public License
  15 # along with this program.  If not, see <http://www.gnu.org/licenses/>.
  16
  17 from collections import namedtuple
  18 # Give a License attribute names: uri, name, abbreviation
  19 License = namedtuple("License", ["abbreviation", "name", "uri"])
  20
  21 SORTED_LICENSES = [
  22     License("All rights reserved", "No license specified", ""),
  23     License("CC BY 3.0", "Creative Commons Attribution Unported 3.0",
  24            "http://creativecommons.org/licenses/by/3.0/"),
  25     License("CC BY-SA 3.0",
  26            "Creative Commons Attribution-ShareAlike Unported 3.0",
  27            "http://creativecommons.org/licenses/by-sa/3.0/"),
  28     License("CC BY-ND 3.0",
  29            "Creative Commons Attribution-NoDerivs 3.0 Unported",
  30            "http://creativecommons.org/licenses/by-nd/3.0/"),
  31     License("CC BY-NC 3.0",
  32           "Creative Commons Attribution-NonCommercial Unported 3.0",
  33           "http://creativecommons.org/licenses/by-nc/3.0/"),
  34     License("CC BY-NC-SA 3.0",
  35            "Creative Commons Attribution-NonCommercial-ShareAlike 3.0 Unported",
  36            "http://creativecommons.org/licenses/by-nc-sa/3.0/"),
  37     License("CC BY-NC-ND 3.0",
  38            "Creative Commons Attribution-NonCommercial-NoDerivs 3.0 Unported",
  39            "http://creativecommons.org/licenses/by-nc-nd/3.0/"),
  40     License("CC0 1.0",
  41            "Creative Commons CC0 1.0 Universal",
  42            "http://creativecommons.org/publicdomain/zero/1.0/"),
  43     License("Public Domain","Public Domain",
  44            "http://creativecommons.org/publicdomain/mark/1.0/"),
  45     ]
  46
  47 # dict {uri: License,...} to enable fast license lookup by uri. Ideally,
  48 # we'd want to use an OrderedDict (python 2.7+) here to avoid having the
  49 # same data in two structures
  50 SUPPORTED_LICENSES = dict(((l.uri, l) for l in SORTED_LICENSES))
  51
  52
  53 def get_license_by_url(url):
  54     """Look up a license by its url and return the License object"""
  55     try:
  56         return SUPPORTED_LICENSES[url]
  57     except KeyError:
  58         # in case of an unknown License, just display the url given
  59         # rather than exploding in the user's face.
  60         return License(url, url, url)
  61
  62
  63 def licenses_as_choices():
  64     """List of (uri, abbreviation) tuples for HTML choice field population
  65
  66     The data seems to be consumed/deleted during usage, so hand over a
  67     throwaway list, rather than just a generator.
  68     """
  69     return [(lic.uri, lic.abbreviation) for lic in SORTED_LICENSES]