test/MC/Hexagon/new-value-check.s

   1 # RUN: not llvm-mc -triple=hexagon < %s 2>&1 | \
   2 # RUN:     FileCheck %s --check-prefix=CHECK-STRICT
   3 # RUN: not llvm-mc -triple=hexagon -relax-nv-checks < %s 2>&1 | \
   4 # RUN:     FileCheck %s --check-prefix=CHECK-RELAXED
   5
   6 # CHECK-STRICT: :10:3: note: Register producer has the opposite predicate sense as consumer
   7 # CHECK-RELAXED: :10:3: note: Register producer has the opposite predicate sense as consumer
   8 {
   9   # invalid: r0 definition predicated on the opposite condition
  10   if (p3) r0 = add(r1, r2)
  11   if (!p3) memb(r20) = r0.new
  12 }
  13
  14 # CHECK-STRICT: :18:3: note: FPU instructions cannot be new-value producers for jumps
  15 # CHECK-RELAXED: :18:3: note: FPU instructions cannot be new-value producers for jumps
  16 # CHECK-RELAXED: :19:3: error: Instruction does not have a valid new register producer
  17 { # invalid: new-value compare-and-jump cannot use floating point value
  18   r0 = sfadd(r1, r2)
  19   if (cmp.eq(r0.new, #0)) jump:nt .
  20 }
  21
  22 # No errors from this point on with the relaxed checks.
  23 # CHECK-RELAXED-NOT: error
  24
  25 # CHECK-STRICT: :28:3: note: Register producer is predicated and consumer is unconditional
  26 {
  27   # valid in relaxed, p0 could always be true
  28   if (p0) r0 = r1
  29   if (cmp.eq(r0.new, #0)) jump:nt .
  30 }
  31
  32 # CHECK-STRICT: :36:3: note: Register producer does not use the same predicate register as the consumer
  33 {
  34   # valid (relaxed): p2 and p3 cannot be proven to violate the new-value
  35   # requirements
  36   if (p3) r0 = add(r1, r2)
  37   if (p2) memb(r20) = r0.new
  38 }
  39
  40 # CHECK-STRICT: :43:3: note: Register producer is predicated and consumer is unconditional
  41 {
  42   # valid (relaxed): p3 could be always true
  43   if (p3) r0 = add(r1, r2)
  44   memb(r20) = r0.new
  45 }
  46
  47
  48 # No errors from this point on with the strict checks.
  49 # CHECK-RELAXED-NOT: error
  50
  51 {
  52   # valid: r0 defined unconditionally
  53   r0 = add(r1, r2)
  54   if (p2) memb(r20) = r0.new
  55 }
  56
  57 {
  58   # valid: r0 definition and use identically predicated
  59   if (p3) r0 = add(r1, r2)
  60   if (p3) memb(r20) = r0.new
  61 }
  62
  63 {
  64   # valid: r0 defined regardless of p0
  65   if (p0) r0 = #0
  66   if (!p0) r0 = #1
  67   if (p0) memb(r20) = r0.new
  68 }
  69