[clang] Handle __declspec() attributes in using
[llvm-project.git] / clang / test / SemaTemplate / temp-param-subst-linear.cpp
blobfd93aa568553f34a003e3903439bad3d1a801bce
1 // RUN: %clang_cc1 -std=c++17 %s -verify
2 // expected-no-diagnostics
4 // This test attempts to ensure that the below template parameter pack
5 // splitting technique executes in linear time in the number of template
6 // parameters. The size of the list below is selected so as to execute
7 // relatively quickly on a "good" compiler and to time out otherwise.
9 template<typename...> struct TypeList;
11 namespace detail {
12 template<unsigned> using Unsigned = unsigned;
13 template<typename T, T ...N> using ListOfNUnsignedsImpl = TypeList<Unsigned<N>...>;
14 template<unsigned N> using ListOfNUnsigneds =
15 __make_integer_seq<ListOfNUnsignedsImpl, unsigned, N>;
17 template<typename T> struct TypeWrapper {
18 template<unsigned> using AsTemplate = T;
21 template<typename ...N> struct Splitter {
22 template<template<N> class ...L,
23 template<unsigned> class ...R> struct Split {
24 using Left = TypeList<L<0>...>;
25 using Right = TypeList<R<0>...>;
30 template<typename TypeList, unsigned N, typename = detail::ListOfNUnsigneds<N>>
31 struct SplitAtIndex;
33 template<typename ...T, unsigned N, typename ...NUnsigneds>
34 struct SplitAtIndex<TypeList<T...>, N, TypeList<NUnsigneds...>> :
35 detail::Splitter<NUnsigneds...>::
36 template Split<detail::TypeWrapper<T>::template AsTemplate...> {};
38 template<typename T, int N> struct Rep : Rep<typename Rep<T, N-1>::type, 1> {};
39 template<typename ...T> struct Rep<TypeList<T...>, 1> { typedef TypeList<T..., T...> type; };
41 using Ints = Rep<TypeList<int>, 14>::type;
43 template<typename T> extern int Size;
44 template<typename ...T> constexpr int Size<TypeList<T...>> = sizeof...(T);
46 using Left = SplitAtIndex<Ints, Size<Ints> / 2>::Left;
47 using Right = SplitAtIndex<Ints, Size<Ints> / 2>::Right;
48 static_assert(Size<Left> == 8192);
49 static_assert(Size<Right> == 8192);
51 template<typename L, typename R> struct Concat;
52 template<typename ...L, typename ...R> struct Concat<TypeList<L...>, TypeList<R...>> {
53 using type = TypeList<L..., R...>;
56 using Ints = Concat<Left, Right>::type;