target: Set peripheral device type consistently in INQUIRY response
[zen-stable.git] / lib / mpi / mpih-cmp.c
blobb2fd39677f1b0823d01e2fd6701e1e1eca44c34f
1 /* mpihelp-sub.c - MPI helper functions
2 * Copyright (C) 1994, 1996 Free Software Foundation, Inc.
3 * Copyright (C) 1998, 1999, 2000, 2001 Free Software Foundation, Inc.
5 * This file is part of GnuPG.
7 * GnuPG is free software; you can redistribute it and/or modify
8 * it under the terms of the GNU General Public License as published by
9 * the Free Software Foundation; either version 2 of the License, or
10 * (at your option) any later version.
12 * GnuPG is distributed in the hope that it will be useful,
13 * but WITHOUT ANY WARRANTY; without even the implied warranty of
14 * MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
15 * GNU General Public License for more details.
17 * You should have received a copy of the GNU General Public License
18 * along with this program; if not, write to the Free Software
19 * Foundation, Inc., 59 Temple Place - Suite 330, Boston, MA 02111-1307, USA
21 * Note: This code is heavily based on the GNU MP Library.
22 * Actually it's the same code with only minor changes in the
23 * way the data is stored; this is to support the abstraction
24 * of an optional secure memory allocation which may be used
25 * to avoid revealing of sensitive data due to paging etc.
26 * The GNU MP Library itself is published under the LGPL;
27 * however I decided to publish this code under the plain GPL.
30 #include "mpi-internal.h"
32 /****************
33 * Compare OP1_PTR/OP1_SIZE with OP2_PTR/OP2_SIZE.
34 * There are no restrictions on the relative sizes of
35 * the two arguments.
36 * Return 1 if OP1 > OP2, 0 if they are equal, and -1 if OP1 < OP2.
38 int mpihelp_cmp(mpi_ptr_t op1_ptr, mpi_ptr_t op2_ptr, mpi_size_t size)
40 mpi_size_t i;
41 mpi_limb_t op1_word, op2_word;
43 for (i = size - 1; i >= 0; i--) {
44 op1_word = op1_ptr[i];
45 op2_word = op2_ptr[i];
46 if (op1_word != op2_word)
47 goto diff;
49 return 0;
51 diff:
52 /* This can *not* be simplified to
53 * op2_word - op2_word
54 * since that expression might give signed overflow. */
55 return (op1_word > op2_word) ? 1 : -1;