lib/libm/src/s_log1p.c

   1 /* @(#)s_log1p.c 5.1 93/09/24 */
   2 /*
   3  * ====================================================
   4  * Copyright (C) 1993 by Sun Microsystems, Inc. All rights reserved.
   5  *
   6  * Developed at SunPro, a Sun Microsystems, Inc. business.
   7  * Permission to use, copy, modify, and distribute this
   8  * software is freely granted, provided that this notice
   9  * is preserved.
  10  * ====================================================
  11  */
  12
  13 /* double log1p(double x)
  14  *
  15  * Method :
  16  *   1. Argument Reduction: find k and f such that
  17  *                      1+x = 2^k * (1+f),
  18  *         where  sqrt(2)/2 < 1+f < sqrt(2) .
  19  *
  20  *      Note. If k=0, then f=x is exact. However, if k!=0, then f
  21  *      may not be representable exactly. In that case, a correction
  22  *      term is need. Let u=1+x rounded. Let c = (1+x)-u, then
  23  *      log(1+x) - log(u) ~ c/u. Thus, we proceed to compute log(u),
  24  *      and add back the correction term c/u.
  25  *      (Note: when x > 2**53, one can simply return log(x))
  26  *
  27  *   2. Approximation of log1p(f).
  28  *      Let s = f/(2+f) ; based on log(1+f) = log(1+s) - log(1-s)
  29  *               = 2s + 2/3 s**3 + 2/5 s**5 + .....,
  30  *               = 2s + s*R
  31  *      We use a special Remes algorithm on [0,0.1716] to generate
  32  *      a polynomial of degree 14 to approximate R The maximum error
  33  *      of this polynomial approximation is bounded by 2**-58.45. In
  34  *      other words,
  35  *                      2      4      6      8      10      12      14
  36  *          R(z) ~ Lp1*s +Lp2*s +Lp3*s +Lp4*s +Lp5*s  +Lp6*s  +Lp7*s
  37  *      (the values of Lp1 to Lp7 are listed in the program)
  38  *      and
  39  *          |      2          14          |     -58.45
  40  *          | Lp1*s +...+Lp7*s    -  R(z) | <= 2
  41  *          |                             |
  42  *      Note that 2s = f - s*f = f - hfsq + s*hfsq, where hfsq = f*f/2.
  43  *      In order to guarantee error in log below 1ulp, we compute log
  44  *      by
  45  *              log1p(f) = f - (hfsq - s*(hfsq+R)).
  46  *
  47  *      3. Finally, log1p(x) = k*ln2 + log1p(f).
  48  *                           = k*ln2_hi+(f-(hfsq-(s*(hfsq+R)+k*ln2_lo)))
  49  *         Here ln2 is split into two floating point number:
  50  *                      ln2_hi + ln2_lo,
  51  *         where n*ln2_hi is always exact for |n| < 2000.
  52  *
  53  * Special cases:
  54  *      log1p(x) is NaN with signal if x < -1 (including -INF) ;
  55  *      log1p(+INF) is +INF; log1p(-1) is -INF with signal;
  56  *      log1p(NaN) is that NaN with no signal.
  57  *
  58  * Accuracy:
  59  *      according to an error analysis, the error is always less than
  60  *      1 ulp (unit in the last place).
  61  *
  62  * Constants:
  63  * The hexadecimal values are the intended ones for the following
  64  * constants. The decimal values may be used, provided that the
  65  * compiler will convert from decimal to binary accurately enough
  66  * to produce the hexadecimal values shown.
  67  *
  68  * Note: Assuming log() return accurate answer, the following
  69  *       algorithm can be used to compute log1p(x) to within a few ULP:
  70  *
  71  *              u = 1+x;
  72  *              if(u==1.0) return x ; else
  73  *                         return log(u)*(x/(u-1.0));
  74  *
  75  *       See HP-15C Advanced Functions Handbook, p.193.
  76  */
  77
  78 #include <float.h>
  79 #include <math.h>
  80
  81 #include "math_private.h"
  82
  83 static const double
  84 ln2_hi  =  6.93147180369123816490e-01,  /* 3fe62e42 fee00000 */
  85 ln2_lo  =  1.90821492927058770002e-10,  /* 3dea39ef 35793c76 */
  86 two54   =  1.80143985094819840000e+16,  /* 43500000 00000000 */
  87 Lp1 = 6.666666666666735130e-01,  /* 3FE55555 55555593 */
  88 Lp2 = 3.999999999940941908e-01,  /* 3FD99999 9997FA04 */
  89 Lp3 = 2.857142874366239149e-01,  /* 3FD24924 94229359 */
  90 Lp4 = 2.222219843214978396e-01,  /* 3FCC71C5 1D8E78AF */
  91 Lp5 = 1.818357216161805012e-01,  /* 3FC74664 96CB03DE */
  92 Lp6 = 1.531383769920937332e-01,  /* 3FC39A09 D078C69F */
  93 Lp7 = 1.479819860511658591e-01;  /* 3FC2F112 DF3E5244 */
  94
  95 static const double zero = 0.0;
  96
  97 double
  98 log1p(double x)
  99 {
 100         double hfsq,f,c,s,z,R,u;
 101         int32_t k,hx,hu,ax;
 102
 103         GET_HIGH_WORD(hx,x);
 104         ax = hx&0x7fffffff;
 105
 106         k = 1;
 107         if (hx < 0x3FDA827A) {                  /* x < 0.41422  */
 108             if(ax>=0x3ff00000) {                /* x <= -1.0 */
 109                 if(x==-1.0) return -two54/zero; /* log1p(-1)=+inf */
 110                 else return (x-x)/(x-x);        /* log1p(x<-1)=NaN */
 111             }
 112             if(ax<0x3e200000) {                 /* |x| < 2**-29 */
 113                 if(two54+x>zero                 /* raise inexact */
 114                     &&ax<0x3c900000)            /* |x| < 2**-54 */
 115                     return x;
 116                 else
 117                     return x - x*x*0.5;
 118             }
 119             if(hx>0||hx<=((int32_t)0xbfd2bec3)) {
 120                 k=0;f=x;hu=1;}  /* -0.2929<x<0.41422 */
 121         }
 122         if (hx >= 0x7ff00000) return x+x;
 123         if(k!=0) {
 124             if(hx<0x43400000) {
 125                 u  = 1.0+x;
 126                 GET_HIGH_WORD(hu,u);
 127                 k  = (hu>>20)-1023;
 128                 c  = (k>0)? 1.0-(u-x):x-(u-1.0);/* correction term */
 129                 c /= u;
 130             } else {
 131                 u  = x;
 132                 GET_HIGH_WORD(hu,u);
 133                 k  = (hu>>20)-1023;
 134                 c  = 0;
 135             }
 136             hu &= 0x000fffff;
 137             if(hu<0x6a09e) {
 138                 SET_HIGH_WORD(u,hu|0x3ff00000); /* normalize u */
 139             } else {
 140                 k += 1;
 141                 SET_HIGH_WORD(u,hu|0x3fe00000); /* normalize u/2 */
 142                 hu = (0x00100000-hu)>>2;
 143             }
 144             f = u-1.0;
 145         }
 146         hfsq=0.5*f*f;
 147         if(hu==0) {     /* |f| < 2**-20 */
 148             if(f==zero) if(k==0) return zero;
 149                         else {c += k*ln2_lo; return k*ln2_hi+c;}
 150             R = hfsq*(1.0-0.66666666666666666*f);
 151             if(k==0) return f-R; else
 152                      return k*ln2_hi-((R-(k*ln2_lo+c))-f);
 153         }
 154         s = f/(2.0+f);
 155         z = s*s;
 156         R = z*(Lp1+z*(Lp2+z*(Lp3+z*(Lp4+z*(Lp5+z*(Lp6+z*Lp7))))));
 157         if(k==0) return f-(hfsq-s*(hfsq+R)); else
 158                  return k*ln2_hi-((hfsq-(s*(hfsq+R)+(k*ln2_lo+c)))-f);
 159 }
 160
 161 #if     LDBL_MANT_DIG == 53
 162 __strong_alias(log1pl, log1p);
 163 #endif  /* LDBL_MANT_DIG == 53 */