merge-recursive: honor diff.algorithm
[git/gitster.git] / match-trees.c
blobf17c74d483f849f9773d4c9c7a7645d05a5e7680
1 #define USE_THE_REPOSITORY_VARIABLE
3 #include "git-compat-util.h"
4 #include "hex.h"
5 #include "match-trees.h"
6 #include "strbuf.h"
7 #include "tree.h"
8 #include "tree-walk.h"
9 #include "object-store-ll.h"
11 static int score_missing(unsigned mode)
13 int score;
15 if (S_ISDIR(mode))
16 score = -1000;
17 else if (S_ISLNK(mode))
18 score = -500;
19 else
20 score = -50;
21 return score;
24 static int score_differs(unsigned mode1, unsigned mode2)
26 int score;
28 if (S_ISDIR(mode1) != S_ISDIR(mode2))
29 score = -100;
30 else if (S_ISLNK(mode1) != S_ISLNK(mode2))
31 score = -50;
32 else
33 score = -5;
34 return score;
37 static int score_matches(unsigned mode1, unsigned mode2)
39 int score;
41 /* Heh, we found SHA-1 collisions between different kind of objects */
42 if (S_ISDIR(mode1) != S_ISDIR(mode2))
43 score = -100;
44 else if (S_ISLNK(mode1) != S_ISLNK(mode2))
45 score = -50;
47 else if (S_ISDIR(mode1))
48 score = 1000;
49 else if (S_ISLNK(mode1))
50 score = 500;
51 else
52 score = 250;
53 return score;
56 static void *fill_tree_desc_strict(struct tree_desc *desc,
57 const struct object_id *hash)
59 void *buffer;
60 enum object_type type;
61 unsigned long size;
63 buffer = repo_read_object_file(the_repository, hash, &type, &size);
64 if (!buffer)
65 die("unable to read tree (%s)", oid_to_hex(hash));
66 if (type != OBJ_TREE)
67 die("%s is not a tree", oid_to_hex(hash));
68 init_tree_desc(desc, hash, buffer, size);
69 return buffer;
72 static int base_name_entries_compare(const struct name_entry *a,
73 const struct name_entry *b)
75 return base_name_compare(a->path, tree_entry_len(a), a->mode,
76 b->path, tree_entry_len(b), b->mode);
80 * Inspect two trees, and give a score that tells how similar they are.
82 static int score_trees(const struct object_id *hash1, const struct object_id *hash2)
84 struct tree_desc one;
85 struct tree_desc two;
86 void *one_buf = fill_tree_desc_strict(&one, hash1);
87 void *two_buf = fill_tree_desc_strict(&two, hash2);
88 int score = 0;
90 for (;;) {
91 int cmp;
93 if (one.size && two.size)
94 cmp = base_name_entries_compare(&one.entry, &two.entry);
95 else if (one.size)
96 /* two lacks this entry */
97 cmp = -1;
98 else if (two.size)
99 /* two has more entries */
100 cmp = 1;
101 else
102 break;
104 if (cmp < 0) {
105 /* path1 does not appear in two */
106 score += score_missing(one.entry.mode);
107 update_tree_entry(&one);
108 } else if (cmp > 0) {
109 /* path2 does not appear in one */
110 score += score_missing(two.entry.mode);
111 update_tree_entry(&two);
112 } else {
113 /* path appears in both */
114 if (!oideq(&one.entry.oid, &two.entry.oid)) {
115 /* they are different */
116 score += score_differs(one.entry.mode,
117 two.entry.mode);
118 } else {
119 /* same subtree or blob */
120 score += score_matches(one.entry.mode,
121 two.entry.mode);
123 update_tree_entry(&one);
124 update_tree_entry(&two);
127 free(one_buf);
128 free(two_buf);
129 return score;
133 * Match one itself and its subtrees with two and pick the best match.
135 static void match_trees(const struct object_id *hash1,
136 const struct object_id *hash2,
137 int *best_score,
138 char **best_match,
139 const char *base,
140 int recurse_limit)
142 struct tree_desc one;
143 void *one_buf = fill_tree_desc_strict(&one, hash1);
145 while (one.size) {
146 const char *path;
147 const struct object_id *elem;
148 unsigned short mode;
149 int score;
151 elem = tree_entry_extract(&one, &path, &mode);
152 if (!S_ISDIR(mode))
153 goto next;
154 score = score_trees(elem, hash2);
155 if (*best_score < score) {
156 free(*best_match);
157 *best_match = xstrfmt("%s%s", base, path);
158 *best_score = score;
160 if (recurse_limit) {
161 char *newbase = xstrfmt("%s%s/", base, path);
162 match_trees(elem, hash2, best_score, best_match,
163 newbase, recurse_limit - 1);
164 free(newbase);
167 next:
168 update_tree_entry(&one);
170 free(one_buf);
174 * A tree "oid1" has a subdirectory at "prefix". Come up with a tree object by
175 * replacing it with another tree "oid2".
177 static int splice_tree(const struct object_id *oid1, const char *prefix,
178 const struct object_id *oid2, struct object_id *result)
180 char *subpath;
181 int toplen;
182 char *buf;
183 unsigned long sz;
184 struct tree_desc desc;
185 unsigned char *rewrite_here;
186 const struct object_id *rewrite_with;
187 struct object_id subtree;
188 enum object_type type;
189 int status;
191 subpath = strchrnul(prefix, '/');
192 toplen = subpath - prefix;
193 if (*subpath)
194 subpath++;
196 buf = repo_read_object_file(the_repository, oid1, &type, &sz);
197 if (!buf)
198 die("cannot read tree %s", oid_to_hex(oid1));
199 init_tree_desc(&desc, oid1, buf, sz);
201 rewrite_here = NULL;
202 while (desc.size) {
203 const char *name;
204 unsigned short mode;
206 tree_entry_extract(&desc, &name, &mode);
207 if (strlen(name) == toplen &&
208 !memcmp(name, prefix, toplen)) {
209 if (!S_ISDIR(mode))
210 die("entry %s in tree %s is not a tree", name,
211 oid_to_hex(oid1));
214 * We cast here for two reasons:
216 * - to flip the "char *" (for the path) to "unsigned
217 * char *" (for the hash stored after it)
219 * - to discard the "const"; this is OK because we
220 * know it points into our non-const "buf"
222 rewrite_here = (unsigned char *)(desc.entry.path +
223 strlen(desc.entry.path) +
225 break;
227 update_tree_entry(&desc);
229 if (!rewrite_here)
230 die("entry %.*s not found in tree %s", toplen, prefix,
231 oid_to_hex(oid1));
232 if (*subpath) {
233 struct object_id tree_oid;
234 oidread(&tree_oid, rewrite_here, the_repository->hash_algo);
235 status = splice_tree(&tree_oid, subpath, oid2, &subtree);
236 if (status)
237 return status;
238 rewrite_with = &subtree;
239 } else {
240 rewrite_with = oid2;
242 hashcpy(rewrite_here, rewrite_with->hash, the_repository->hash_algo);
243 status = write_object_file(buf, sz, OBJ_TREE, result);
244 free(buf);
245 return status;
249 * We are trying to come up with a merge between one and two that
250 * results in a tree shape similar to one. The tree two might
251 * correspond to a subtree of one, in which case it needs to be
252 * shifted down by prefixing otherwise empty directories. On the
253 * other hand, it could cover tree one and we might need to pick a
254 * subtree of it.
256 void shift_tree(struct repository *r,
257 const struct object_id *hash1,
258 const struct object_id *hash2,
259 struct object_id *shifted,
260 int depth_limit)
262 char *add_prefix;
263 char *del_prefix;
264 int add_score, del_score;
267 * NEEDSWORK: this limits the recursion depth to hardcoded
268 * value '2' to avoid excessive overhead.
270 if (!depth_limit)
271 depth_limit = 2;
273 add_score = del_score = score_trees(hash1, hash2);
274 add_prefix = xcalloc(1, 1);
275 del_prefix = xcalloc(1, 1);
278 * See if one's subtree resembles two; if so we need to prefix
279 * two with a few fake trees to match the prefix.
281 match_trees(hash1, hash2, &add_score, &add_prefix, "", depth_limit);
284 * See if two's subtree resembles one; if so we need to
285 * pick only subtree of two.
287 match_trees(hash2, hash1, &del_score, &del_prefix, "", depth_limit);
289 /* Assume we do not have to do any shifting */
290 oidcpy(shifted, hash2);
292 if (add_score < del_score) {
293 /* We need to pick a subtree of two */
294 unsigned short mode;
296 if (!*del_prefix)
297 return;
299 if (get_tree_entry(r, hash2, del_prefix, shifted, &mode))
300 die("cannot find path %s in tree %s",
301 del_prefix, oid_to_hex(hash2));
302 return;
305 if (!*add_prefix)
306 return;
308 splice_tree(hash1, add_prefix, hash2, shifted);
312 * The user says the trees will be shifted by this much.
313 * Unfortunately we cannot fundamentally tell which one to
314 * be prefixed, as recursive merge can work in either direction.
316 void shift_tree_by(struct repository *r,
317 const struct object_id *hash1,
318 const struct object_id *hash2,
319 struct object_id *shifted,
320 const char *shift_prefix)
322 struct object_id sub1, sub2;
323 unsigned short mode1, mode2;
324 unsigned candidate = 0;
326 /* Can hash2 be a tree at shift_prefix in tree hash1? */
327 if (!get_tree_entry(r, hash1, shift_prefix, &sub1, &mode1) &&
328 S_ISDIR(mode1))
329 candidate |= 1;
331 /* Can hash1 be a tree at shift_prefix in tree hash2? */
332 if (!get_tree_entry(r, hash2, shift_prefix, &sub2, &mode2) &&
333 S_ISDIR(mode2))
334 candidate |= 2;
336 if (candidate == 3) {
337 /* Both are plausible -- we need to evaluate the score */
338 int best_score = score_trees(hash1, hash2);
339 int score;
341 candidate = 0;
342 score = score_trees(&sub1, hash2);
343 if (score > best_score) {
344 candidate = 1;
345 best_score = score;
347 score = score_trees(&sub2, hash1);
348 if (score > best_score)
349 candidate = 2;
352 if (!candidate) {
353 /* Neither is plausible -- do not shift */
354 oidcpy(shifted, hash2);
355 return;
358 if (candidate == 1)
360 * shift tree2 down by adding shift_prefix above it
361 * to match tree1.
363 splice_tree(hash1, shift_prefix, hash2, shifted);
364 else
366 * shift tree2 up by removing shift_prefix from it
367 * to match tree1.
369 oidcpy(shifted, &sub2);