1 // SPDX-License-Identifier: GPL-2.0
3 * Copyright (C) 2003 Bernardo Innocenti <bernie@develer.com>
5 * Based on former do_div() implementation from asm-parisc/div64.h:
6 * Copyright (C) 1999 Hewlett-Packard Co
7 * Copyright (C) 1999 David Mosberger-Tang <davidm@hpl.hp.com>
10 * Generic C version of 64bit/32bit division and modulo, with
11 * 64bit result and 32bit remainder.
13 * The fast case for (n>>32 == 0) is handled inline by do_div().
15 * Code generated for this function might be very inefficient
16 * for some CPUs. __div64_32() can be overridden by linking arch-specific
17 * assembly versions such as arch/ppc/lib/div64.S and arch/sh/lib/div64.S
18 * or by defining a preprocessor macro in arch/include/asm/div64.h.
21 #include <linux/bitops.h>
22 #include <linux/export.h>
23 #include <linux/math.h>
24 #include <linux/math64.h>
25 #include <linux/log2.h>
27 /* Not needed on 64bit architectures */
28 #if BITS_PER_LONG == 32
31 uint32_t __attribute__((weak
)) __div64_32(uint64_t *n
, uint32_t base
)
36 uint32_t high
= rem
>> 32;
38 /* Reduce the thing a bit first */
42 res
= (uint64_t) high
<< 32;
43 rem
-= (uint64_t) (high
*base
) << 32;
46 while ((int64_t)b
> 0 && b
< rem
) {
63 EXPORT_SYMBOL(__div64_32
);
67 * div_s64_rem - signed 64bit divide with 64bit divisor and remainder
68 * @dividend: 64bit dividend
69 * @divisor: 64bit divisor
70 * @remainder: 64bit remainder
73 s64
div_s64_rem(s64 dividend
, s32 divisor
, s32
*remainder
)
78 quotient
= div_u64_rem(-dividend
, abs(divisor
), (u32
*)remainder
);
79 *remainder
= -*remainder
;
83 quotient
= div_u64_rem(dividend
, abs(divisor
), (u32
*)remainder
);
89 EXPORT_SYMBOL(div_s64_rem
);
93 * div64_u64_rem - unsigned 64bit divide with 64bit divisor and remainder
94 * @dividend: 64bit dividend
95 * @divisor: 64bit divisor
96 * @remainder: 64bit remainder
98 * This implementation is a comparable to algorithm used by div64_u64.
99 * But this operation, which includes math for calculating the remainder,
100 * is kept distinct to avoid slowing down the div64_u64 operation on 32bit
103 #ifndef div64_u64_rem
104 u64
div64_u64_rem(u64 dividend
, u64 divisor
, u64
*remainder
)
106 u32 high
= divisor
>> 32;
111 quot
= div_u64_rem(dividend
, divisor
, &rem32
);
115 quot
= div_u64(dividend
>> n
, divisor
>> n
);
120 *remainder
= dividend
- quot
* divisor
;
121 if (*remainder
>= divisor
) {
123 *remainder
-= divisor
;
129 EXPORT_SYMBOL(div64_u64_rem
);
133 * div64_u64 - unsigned 64bit divide with 64bit divisor
134 * @dividend: 64bit dividend
135 * @divisor: 64bit divisor
137 * This implementation is a modified version of the algorithm proposed
138 * by the book 'Hacker's Delight'. The original source and full proof
139 * can be found here and is available for use without restriction.
141 * 'http://www.hackersdelight.org/hdcodetxt/divDouble.c.txt'
144 u64
div64_u64(u64 dividend
, u64 divisor
)
146 u32 high
= divisor
>> 32;
150 quot
= div_u64(dividend
, divisor
);
153 quot
= div_u64(dividend
>> n
, divisor
>> n
);
157 if ((dividend
- quot
* divisor
) >= divisor
)
163 EXPORT_SYMBOL(div64_u64
);
167 * div64_s64 - signed 64bit divide with 64bit divisor
168 * @dividend: 64bit dividend
169 * @divisor: 64bit divisor
172 s64
div64_s64(s64 dividend
, s64 divisor
)
176 quot
= div64_u64(abs(dividend
), abs(divisor
));
177 t
= (dividend
^ divisor
) >> 63;
179 return (quot
^ t
) - t
;
181 EXPORT_SYMBOL(div64_s64
);
184 #endif /* BITS_PER_LONG == 32 */
187 * Iterative div/mod for use when dividend is not expected to be much
188 * bigger than divisor.
190 u32
iter_div_u64_rem(u64 dividend
, u32 divisor
, u64
*remainder
)
192 return __iter_div_u64_rem(dividend
, divisor
, remainder
);
194 EXPORT_SYMBOL(iter_div_u64_rem
);
196 #ifndef mul_u64_u64_div_u64
197 u64
mul_u64_u64_div_u64(u64 a
, u64 b
, u64 c
)
199 u64 res
= 0, div
, rem
;
202 /* can a * b overflow ? */
203 if (ilog2(a
) + ilog2(b
) > 62) {
205 * (b * a) / c is equal to
210 * if nothing overflows. Can the 1st multiplication
211 * overflow? Yes, but we do not care: this can only
212 * happen if the end result can't fit in u64 anyway.
214 * So the code below does
219 div
= div64_u64_rem(b
, c
, &rem
);
223 shift
= ilog2(a
) + ilog2(b
) - 62;
233 return res
+ div64_u64(a
* b
, c
);