1 // SPDX-License-Identifier: GPL-2.0
3 * Copyright (C) 2007 Oracle. All rights reserved.
6 #include <linux/sched.h>
9 #include "print-tree.h"
10 #include "transaction.h"
14 * Defrag all the leaves in a given btree.
15 * Read all the leaves and try to get key order to
16 * better reflect disk order
19 int btrfs_defrag_leaves(struct btrfs_trans_handle
*trans
,
20 struct btrfs_root
*root
)
22 struct btrfs_path
*path
= NULL
;
30 if (root
->fs_info
->extent_root
== root
) {
32 * there's recursion here right now in the tree locking,
33 * we can't defrag the extent root without deadlock
38 if (!test_bit(BTRFS_ROOT_SHAREABLE
, &root
->state
))
41 path
= btrfs_alloc_path();
45 level
= btrfs_header_level(root
->node
);
50 if (root
->defrag_progress
.objectid
== 0) {
51 struct extent_buffer
*root_node
;
54 root_node
= btrfs_lock_root_node(root
);
55 btrfs_set_lock_blocking_write(root_node
);
56 nritems
= btrfs_header_nritems(root_node
);
57 root
->defrag_max
.objectid
= 0;
58 /* from above we know this is not a leaf */
59 btrfs_node_key_to_cpu(root_node
, &root
->defrag_max
,
61 btrfs_tree_unlock(root_node
);
62 free_extent_buffer(root_node
);
63 memset(&key
, 0, sizeof(key
));
65 memcpy(&key
, &root
->defrag_progress
, sizeof(key
));
70 ret
= btrfs_search_forward(root
, &key
, path
, BTRFS_OLDEST_GENERATION
);
77 btrfs_release_path(path
);
79 * We don't need a lock on a leaf. btrfs_realloc_node() will lock all
80 * leafs from path->nodes[1], so set lowest_level to 1 to avoid later
81 * a deadlock (attempting to write lock an already write locked leaf).
83 path
->lowest_level
= 1;
84 wret
= btrfs_search_slot(trans
, root
, &key
, path
, 0, 1);
90 if (!path
->nodes
[1]) {
95 * The node at level 1 must always be locked when our path has
96 * keep_locks set and lowest_level is 1, regardless of the value of
99 BUG_ON(path
->locks
[1] == 0);
100 ret
= btrfs_realloc_node(trans
, root
,
103 &root
->defrag_progress
);
105 WARN_ON(ret
== -EAGAIN
);
109 * Now that we reallocated the node we can find the next key. Note that
110 * btrfs_find_next_key() can release our path and do another search
111 * without COWing, this is because even with path->keep_locks = 1,
112 * btrfs_search_slot() / ctree.c:unlock_up() does not keeps a lock on a
113 * node when path->slots[node_level - 1] does not point to the last
114 * item or a slot beyond the last item (ctree.c:unlock_up()). Therefore
115 * we search for the next key after reallocating our node.
117 path
->slots
[1] = btrfs_header_nritems(path
->nodes
[1]);
118 next_key_ret
= btrfs_find_next_key(root
, path
, &key
, 1,
119 BTRFS_OLDEST_GENERATION
);
120 if (next_key_ret
== 0) {
121 memcpy(&root
->defrag_progress
, &key
, sizeof(key
));
125 btrfs_free_path(path
);
126 if (ret
== -EAGAIN
) {
127 if (root
->defrag_max
.objectid
> root
->defrag_progress
.objectid
)
129 if (root
->defrag_max
.type
> root
->defrag_progress
.type
)
131 if (root
->defrag_max
.offset
> root
->defrag_progress
.offset
)
136 if (ret
!= -EAGAIN
) {
137 memset(&root
->defrag_progress
, 0,
138 sizeof(root
->defrag_progress
));
139 root
->defrag_trans_start
= trans
->transid
;