1 //===- ReservoirSampler.cpp - Tests for the ReservoirSampler --------------===//
3 // Part of the LLVM Project, under the Apache License v2.0 with LLVM Exceptions.
4 // See https://llvm.org/LICENSE.txt for license information.
5 // SPDX-License-Identifier: Apache-2.0 WITH LLVM-exception
7 //===----------------------------------------------------------------------===//
9 #include "llvm/FuzzMutate/Random.h"
10 #include "gtest/gtest.h"
15 TEST(ReservoirSamplerTest
, OneItem
) {
17 auto Sampler
= makeSampler(Rand
, 7, 1);
18 ASSERT_FALSE(Sampler
.isEmpty());
19 ASSERT_EQ(7, Sampler
.getSelection());
22 TEST(ReservoirSamplerTest
, NoWeight
) {
24 auto Sampler
= makeSampler(Rand
, 7, 0);
25 ASSERT_TRUE(Sampler
.isEmpty());
28 TEST(ReservoirSamplerTest
, Uniform
) {
31 // Run three chi-squared tests to check that the distribution is reasonably
33 std::vector
<int> Items
= {0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
36 for (int Run
= 0; Run
< 3; ++Run
) {
37 std::vector
<int> Counts(Items
.size(), 0);
39 // We need $np_s > 5$ at minimum, but we're better off going a couple of
40 // orders of magnitude larger.
41 int N
= Items
.size() * 5 * 100;
42 for (int I
= 0; I
< N
; ++I
) {
43 auto Sampler
= makeSampler(Rand
, Items
);
44 Counts
[Sampler
.getSelection()] += 1;
47 // Knuth. TAOCP Vol. 2, 3.3.1 (8):
48 // $V = \frac{1}{n} \sum_{s=1}^{k} \left(\frac{Y_s^2}{p_s}\right) - n$
49 double Ps
= 1.0 / Items
.size();
53 double V
= (Sum
/ N
) - N
;
55 assert(Items
.size() == 10 && "Our chi-squared values assume 10 items");
56 // Since we have 10 items, there are 9 degrees of freedom and the table of
57 // chi-squared values is as follows:
59 // | p=1% | 5% | 25% | 50% | 75% | 95% | 99% |
60 // v=9 | 2.088 | 3.325 | 5.899 | 8.343 | 11.39 | 16.92 | 21.67 |
62 // Check that we're in the likely range of results.
63 //if (V < 2.088 || V > 21.67)
64 if (V
< 2.088 || V
> 21.67)
67 EXPECT_LT(Failures
, 3) << "Non-uniform distribution?";