1 ; Test that elimination of logical operators works with
2 ; arbitrary precision integers.
3 ; RUN: opt < %s -instcombine -S | \
4 ; RUN: not grep {(and\|xor\|add\|shl\|shr)}
7 define i33 @test1(i33 %x) {
8 %tmp.1 = and i33 %x, 65535 ; <i33> [#uses=1]
9 %tmp.2 = xor i33 %tmp.1, -32768 ; <i33> [#uses=1]
10 %tmp.3 = add i33 %tmp.2, 32768 ; <i33> [#uses=1]
14 define i33 @test2(i33 %x) {
15 %tmp.1 = and i33 %x, 65535 ; <i33> [#uses=1]
16 %tmp.2 = xor i33 %tmp.1, 32768 ; <i33> [#uses=1]
17 %tmp.3 = add i33 %tmp.2, -32768 ; <i33> [#uses=1]
21 define i33 @test3(i16 %P) {
22 %tmp.1 = zext i16 %P to i33 ; <i33> [#uses=1]
23 %tmp.4 = xor i33 %tmp.1, 32768 ; <i33> [#uses=1]
24 %tmp.5 = add i33 %tmp.4, -32768 ; <i33> [#uses=1]
28 define i33 @test5(i33 %x) {
29 %tmp.1 = and i33 %x, 254
30 %tmp.2 = xor i33 %tmp.1, 128
31 %tmp.3 = add i33 %tmp.2, -128
35 define i33 @test6(i33 %x) {
36 %tmp.2 = shl i33 %x, 16 ; <i33> [#uses=1]
37 %tmp.4 = lshr i33 %tmp.2, 16 ; <i33> [#uses=1]