1 ; RUN: llvm-as < %s | opt -loop-reduce | llvm-dis | grep phi | count 1
3 ; This testcase should have ONE stride 18 indvar, the other use should have a
4 ; loop invariant value (B) added to it inside of the loop, instead of having
5 ; a whole indvar based on B for it.
9 define void @test(i32 %B) {
12 Loop: ; preds = %Loop, %0
13 %IV = phi i32 [ 0, %0 ], [ %IVn, %Loop ] ; <i32> [#uses=3]
14 %C = mul i32 %IV, 18 ; <i32> [#uses=1]
15 %D = mul i32 %IV, 18 ; <i32> [#uses=1]
16 %E = add i32 %D, %B ; <i32> [#uses=1]
17 %cnd = call i1 @cond( i32 %E ) ; <i1> [#uses=1]
18 call i1 @cond( i32 %C ) ; <i1>:1 [#uses=0]
19 %IVn = add i32 %IV, 1 ; <i32> [#uses=1]
20 br i1 %cnd, label %Loop, label %Out