1 /* $NetBSD: compat_modf_ieee754.c,v 1.4 2010/04/23 19:04:54 drochner Exp $ */
4 * Copyright (c) 1994, 1995 Carnegie-Mellon University.
7 * Author: Chris G. Demetriou
9 * Permission to use, copy, modify and distribute this software and
10 * its documentation is hereby granted, provided that both the copyright
11 * notice and this permission notice appear in all copies of the
12 * software, derivative works or modified versions, and any portions
13 * thereof, and that both notices appear in supporting documentation.
15 * CARNEGIE MELLON ALLOWS FREE USE OF THIS SOFTWARE IN ITS "AS IS"
16 * CONDITION. CARNEGIE MELLON DISCLAIMS ANY LIABILITY OF ANY KIND
17 * FOR ANY DAMAGES WHATSOEVER RESULTING FROM THE USE OF THIS SOFTWARE.
19 * Carnegie Mellon requests users of this software to return to
21 * Software Distribution Coordinator or Software.Distribution@CS.CMU.EDU
22 * School of Computer Science
23 * Carnegie Mellon University
24 * Pittsburgh PA 15213-3890
26 * any improvements or extensions that they make and grant Carnegie the
27 * rights to redistribute these changes.
30 #include <sys/types.h>
31 #include <machine/ieee.h>
34 double modf(double, double *);
37 * double modf(double val, double *iptr)
38 * returns: f and i such that |f| < 1.0, (f + i) = val, and
39 * sign(f) == sign(i) == sign(val).
41 * Beware signedness when doing subtraction, and also operand size!
44 modf(double val
, double *iptr
)
46 union ieee_double_u u
, v
;
50 * If input is +/-Inf or NaN, return +/-0 or NaN.
53 if (u
.dblu_dbl
.dbl_exp
== DBL_EXP_INFNAN
) {
55 return (0.0 / u
.dblu_d
);
59 * If input can't have a fractional part, return
60 * (appropriately signed) zero, and make i be the input.
62 if ((int)u
.dblu_dbl
.dbl_exp
- DBL_EXP_BIAS
> DBL_FRACBITS
- 1) {
65 v
.dblu_dbl
.dbl_sign
= u
.dblu_dbl
.dbl_sign
;
70 * If |input| < 1.0, return it, and set i to the appropriately
73 if (u
.dblu_dbl
.dbl_exp
< DBL_EXP_BIAS
) {
75 v
.dblu_dbl
.dbl_sign
= u
.dblu_dbl
.dbl_sign
;
81 * There can be a fractional part of the input.
82 * If you look at the math involved for a few seconds, it's
83 * plain to see that the integral part is the input, with the
84 * low (DBL_FRACBITS - (exponent - DBL_EXP_BIAS)) bits zeroed,
85 * the fractional part is the part with the rest of the
86 * bits zeroed. Just zeroing the high bits to get the
87 * fractional part would yield a fraction in need of
88 * normalization. Therefore, we take the easy way out, and
89 * just use subtraction to get the fractional part.
92 /* Zero the low bits of the fraction, the sleazy way. */
93 frac
= ((u_int64_t
)v
.dblu_dbl
.dbl_frach
<< 32) + v
.dblu_dbl
.dbl_fracl
;
94 frac
>>= DBL_FRACBITS
- (u
.dblu_dbl
.dbl_exp
- DBL_EXP_BIAS
);
95 frac
<<= DBL_FRACBITS
- (u
.dblu_dbl
.dbl_exp
- DBL_EXP_BIAS
);
96 v
.dblu_dbl
.dbl_fracl
= (unsigned int)frac
& 0xffffffff;
97 v
.dblu_dbl
.dbl_frach
= (unsigned int)(frac
>> 32);
100 u
.dblu_d
-= v
.dblu_d
;
101 u
.dblu_dbl
.dbl_sign
= v
.dblu_dbl
.dbl_sign
;