1 /* $NetBSD: div.c,v 1.8 2012/06/25 22:32:45 abs Exp $ */
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35 #include <sys/cdefs.h>
36 #if defined(LIBC_SCCS) && !defined(lint)
38 static char sccsid
[] = "@(#)div.c 8.1 (Berkeley) 6/4/93";
40 __RCSID("$NetBSD: div.c,v 1.8 2012/06/25 22:32:45 abs Exp $");
42 #endif /* LIBC_SCCS and not lint */
44 #include <stdlib.h> /* div_t */
47 div(int num
, int denom
)
54 * The ANSI standard says that |r.quot| <= |n/d|, where
55 * n/d is to be computed in infinite precision. In other
56 * words, we should always truncate the quotient towards
59 * Machine division and remainer may work either way when
60 * one or both of n or d is negative. If only one is
61 * negative and r.quot has been truncated towards -inf,
62 * r.rem will have the same sign as denom and the opposite
63 * sign of num; if both are negative and r.quot has been
64 * truncated towards -inf, r.rem will be positive (will
65 * have the opposite sign of num). These are considered
68 * If both are num and denom are positive, r will always
71 * This all boils down to:
72 * if num >= 0, but r.rem < 0, we got the wrong answer.
73 * In that case, to get the right answer, add 1 to r.quot and
74 * subtract denom from r.rem.
76 if (num
>= 0 && r
.rem
< 0) {