3 A modulo algrithm. The point of this test is that it triggers otherwise untested peephole rules.
8 #define MSB_SET(x) ((x >> (8*sizeof(x)-1)) & 1)
11 modulong (unsigned long a
, unsigned long b
)
13 unsigned char count
= 0;
39 ASSERT (modulong (42ul, 23ul) == 42ul % 23ul);