2 * 802.11 utility definitions
4 * Wireshark - Network traffic analyzer
5 * By Gerald Combs <gerald@wireshark.org>
6 * Copyright 2007 Gerald Combs
8 * SPDX-License-Identifier: GPL-2.0-or-later
12 #include "802_11-utils.h"
13 #include <wsutil/array.h>
15 typedef struct freq_cvt_s
{
16 unsigned fmin
; /* Minimum frequency in MHz */
17 unsigned fmax
; /* Maximum frequency in MHz */
18 int cmin
; /* Minimum/base channel */
19 bool is_bg
; /* B/G channel? */
22 #define FREQ_STEP 5 /* MHz. This seems to be consistent, thankfully */
25 * XXX - Japanese channels 182 through 196 actually have center
26 * frequencies that are off by 2.5 MHz from these values, according
27 * to the IEEE standard, although the table in ARIB STD T-71 version 5.2:
29 * http://www.arib.or.jp/english/html/overview/doc/1-STD-T71v5_2.pdf
31 * section 5.3.8.3.3 doesn't show that.
33 * XXX - what about the U.S. public safety 4.9 GHz band?
35 * XXX - what about 802.11ad?
37 static freq_cvt_t freq_cvt
[] = {
38 { 2412, 2472, 1, true }, /* IEEE Std 802.11-2020: Section 15.4.4.3 and Annex E */
39 { 2484, 2484, 14, true }, /* IEEE Std 802.11-2020: Section 15.4.4.3 and Annex E */
40 { 5000, 5925, 0, false }, /* IEEE Std 802.11-2020: Annex E */
41 { 5950, 7125, 0, false }, /* IEEE Std 802.11ax-2021: Annex E */
42 { 4910, 4980, 182, false },
45 #define NUM_FREQ_CVT array_length(freq_cvt)
46 #define MAX_CHANNEL(fc) ( (int) ((fc.fmax - fc.fmin) / FREQ_STEP) + fc.cmin )
49 * Get channel number given a Frequency
52 ieee80211_mhz_to_chan(unsigned freq
) {
55 for (i
= 0; i
< NUM_FREQ_CVT
; i
++) {
56 if (freq
>= freq_cvt
[i
].fmin
&& freq
<= freq_cvt
[i
].fmax
) {
57 return ((freq
- freq_cvt
[i
].fmin
) / FREQ_STEP
) + freq_cvt
[i
].cmin
;
64 * Get Frequency given a Channel number
66 * XXX - Because channel numbering schemes for 2.4 and 5 overlap with 6 GHz,
67 * this function may not return the correct channel. For example, the frequency
68 * for channel 1 in 2.4 GHz band is 2412 MHz, while the frequency for channel 1
69 * in the 6 GHz band is 5955 MHz. To resolve this problem, this function needs
70 * to take a starting frequency to convert channel to frequencies correctly.
71 * Unfortunately, this is not possible in some cases, so for now, the order on
72 * which frequency ranges are defined will favor 2.4 and 5 GHz over 6 GHz.
75 ieee80211_chan_to_mhz(int chan
, bool is_bg
) {
78 for (i
= 0; i
< NUM_FREQ_CVT
; i
++) {
79 if (is_bg
== freq_cvt
[i
].is_bg
&&
80 chan
>= freq_cvt
[i
].cmin
&& chan
<= MAX_CHANNEL(freq_cvt
[i
])) {
81 return ((chan
- freq_cvt
[i
].cmin
) * FREQ_STEP
) + freq_cvt
[i
].fmin
;
88 * Get Frequency given a Channel number and band.
91 ieee80211_chan_band_to_mhz(int chan
, bool is_bg
, bool is_6ghz
) {
98 for (i
= start_idx
; i
< NUM_FREQ_CVT
; i
++) {
99 if (is_bg
== freq_cvt
[i
].is_bg
&&
100 chan
>= freq_cvt
[i
].cmin
&& chan
<= MAX_CHANNEL(freq_cvt
[i
])) {
101 return ((chan
- freq_cvt
[i
].cmin
) * FREQ_STEP
) + freq_cvt
[i
].fmin
;
108 * Get channel representation string given a Frequency
111 ieee80211_mhz_to_str(unsigned freq
){
112 int chan
= ieee80211_mhz_to_chan(freq
);
114 if (FREQ_IS_BG(freq
)) {
116 } else if (FREQ_IS_6G(freq
)) {
123 return ws_strdup_printf("%u", freq
);
125 return ws_strdup_printf("%u [%s %u]", freq
, band
,
136 * indent-tabs-mode: nil
139 * ex: set shiftwidth=4 tabstop=8 expandtab:
140 * :indentSize=4:tabSize=8:noTabs=true: