libutil: add O_NOCTTY back to old pty open code
[minix.git] / lib / libc / compat / gen / compat_modf_ieee754.c
blob660697d6fe09e0c57c71b682a3af70850b2cd610
1 /* $NetBSD: compat_modf_ieee754.c,v 1.4 2010/04/23 19:04:54 drochner Exp $ */
3 /*
4 * Copyright (c) 1994, 1995 Carnegie-Mellon University.
5 * All rights reserved.
7 * Author: Chris G. Demetriou
8 *
9 * Permission to use, copy, modify and distribute this software and
10 * its documentation is hereby granted, provided that both the copyright
11 * notice and this permission notice appear in all copies of the
12 * software, derivative works or modified versions, and any portions
13 * thereof, and that both notices appear in supporting documentation.
15 * CARNEGIE MELLON ALLOWS FREE USE OF THIS SOFTWARE IN ITS "AS IS"
16 * CONDITION. CARNEGIE MELLON DISCLAIMS ANY LIABILITY OF ANY KIND
17 * FOR ANY DAMAGES WHATSOEVER RESULTING FROM THE USE OF THIS SOFTWARE.
19 * Carnegie Mellon requests users of this software to return to
21 * Software Distribution Coordinator or Software.Distribution@CS.CMU.EDU
22 * School of Computer Science
23 * Carnegie Mellon University
24 * Pittsburgh PA 15213-3890
26 * any improvements or extensions that they make and grant Carnegie the
27 * rights to redistribute these changes.
30 #include <sys/types.h>
31 #include <machine/ieee.h>
32 #include <errno.h>
34 double modf(double, double *);
37 * double modf(double val, double *iptr)
38 * returns: f and i such that |f| < 1.0, (f + i) = val, and
39 * sign(f) == sign(i) == sign(val).
41 * Beware signedness when doing subtraction, and also operand size!
43 double
44 modf(double val, double *iptr)
46 union ieee_double_u u, v;
47 u_int64_t frac;
50 * If input is +/-Inf or NaN, return +/-0 or NaN.
52 u.dblu_d = val;
53 if (u.dblu_dbl.dbl_exp == DBL_EXP_INFNAN) {
54 *iptr = u.dblu_d;
55 return (0.0 / u.dblu_d);
59 * If input can't have a fractional part, return
60 * (appropriately signed) zero, and make i be the input.
62 if ((int)u.dblu_dbl.dbl_exp - DBL_EXP_BIAS > DBL_FRACBITS - 1) {
63 *iptr = u.dblu_d;
64 v.dblu_d = 0.0;
65 v.dblu_dbl.dbl_sign = u.dblu_dbl.dbl_sign;
66 return (v.dblu_d);
70 * If |input| < 1.0, return it, and set i to the appropriately
71 * signed zero.
73 if (u.dblu_dbl.dbl_exp < DBL_EXP_BIAS) {
74 v.dblu_d = 0.0;
75 v.dblu_dbl.dbl_sign = u.dblu_dbl.dbl_sign;
76 *iptr = v.dblu_d;
77 return (u.dblu_d);
81 * There can be a fractional part of the input.
82 * If you look at the math involved for a few seconds, it's
83 * plain to see that the integral part is the input, with the
84 * low (DBL_FRACBITS - (exponent - DBL_EXP_BIAS)) bits zeroed,
85 * the fractional part is the part with the rest of the
86 * bits zeroed. Just zeroing the high bits to get the
87 * fractional part would yield a fraction in need of
88 * normalization. Therefore, we take the easy way out, and
89 * just use subtraction to get the fractional part.
91 v.dblu_d = u.dblu_d;
92 /* Zero the low bits of the fraction, the sleazy way. */
93 frac = ((u_int64_t)v.dblu_dbl.dbl_frach << 32) + v.dblu_dbl.dbl_fracl;
94 frac >>= DBL_FRACBITS - (u.dblu_dbl.dbl_exp - DBL_EXP_BIAS);
95 frac <<= DBL_FRACBITS - (u.dblu_dbl.dbl_exp - DBL_EXP_BIAS);
96 v.dblu_dbl.dbl_fracl = (unsigned int)frac & 0xffffffff;
97 v.dblu_dbl.dbl_frach = (unsigned int)(frac >> 32);
98 *iptr = v.dblu_d;
100 u.dblu_d -= v.dblu_d;
101 u.dblu_dbl.dbl_sign = v.dblu_dbl.dbl_sign;
102 return (u.dblu_d);